Software Engineering

How to Check for Factor in Python

The challenge

This function should test if the factor is a factor of base.

Return true if it is a factor or false if it is not.

About factors

Factors are numbers you can multiply together to get another number.

2 and 3 are factors of 6 because: 2 * 3 = 6

  • You can find a factor by dividing numbers. If the remainder is 0 then the number is a factor.
  • You can use the mod operator (%) in most languages to check for a remainder


2 is not a factor of 7 because: 7 % 2 = 1

Note: base is a non-negative number, factor is a positive number.

The solution in Python

Option 1:

def check_for_factor(base, factor):
    return base/factor == int(base/factor)

Option 2:

def check_for_factor(base, factor):
    return base % factor == 0

Option 3:

check_for_factor=lambda a,b:not a%b

Test cases to validate our solution

import test
from solution import check_for_factor

@test.describe("Fixed Tests")
def fixed_tests():"Should return True")
    def should_return_true():
        test.assert_equals(check_for_factor(10, 2), True)
        test.assert_equals(check_for_factor(63, 7), True)
        test.assert_equals(check_for_factor(2450, 5), True)
        test.assert_equals(check_for_factor(24612, 3), True)
   "Should return False")
    def should_return_false():
        test.assert_equals(check_for_factor(9, 2), False)
        test.assert_equals(check_for_factor(653, 7), False)
        test.assert_equals(check_for_factor(2453, 5), False)
        test.assert_equals(check_for_factor(24617, 3), False)